F(4)-7=5n^2+2n

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Solution for F(4)-7=5n^2+2n equation: 



(4)-7=5F^2+2F

We move all terms to the left:

(4)-7-(5F^2+2F)=0

We add all the numbers together, and all the variables

-(5F^2+2F)-3=0

We get rid of parentheses

-5F^2-2F-3=0

a = -5; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·(-5)·(-3)
Δ = -56
Delta is less than zero, so there is no solution for the equation

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